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正常RAbin

呜咩,2026-04-24 01:54
Python
from Crypto.Util.number import long_to_bytes import gmpy2 p = 9109516638675942224743777995148545134530013554275734886455448931671863095997507569243594319863772181509837924098591463427796446396931029539716403962408943 q = 10740686879425642178311117871838817113230054398803925695044823186721569157087087148128828336409020272313601366223259400603169731251187486908754100440733959 c = 140655211554927678503347324092478047438045251131293471286425677406100240063574753515992620829045521915462201396598103882338968738138846160402436956319724406025 n = p * q mp = pow(c, (p+1)//4, p) mq = pow(c, (q+1)//4, q) yp = gmpy2.invert(p, q) yq = gmpy2.invert(q, p) r1 = (mp * yq * q + mq * yp * p) % n r2 = (mp * yq * q - mq * yp * p) % n r3 = (-mp * yq * q + mq * yp * p) % n r4 = (-mp * yq * q - mq * yp * p) % n for r in [r1, r2, r3, r4]: try: msg = long_to_bytes(r).decode() if 'flag' in msg: print("找到 flag:", msg) except: pass
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